
Proofs concerning isosceles triangles (video) | Khan Academy
Sal proves that the base angles in isosceles triangles are congruent, and conversely, that triangles with congruent base angles are isosceles. He also proves that the perpendicular to the base of an …
Khan Academy | Khan Academy
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Triangle congruence review (article) | Khan Academy
Review the triangle congruence criteria and use them to determine congruent triangles.
Congruence | Geometry (all content) | Math | Khan Academy
Learn what it means for two figures to be congruent, and how to determine whether two figures are congruent or not. Use this immensely important concept to prove various geometric theorems about …
Finding angles in isosceles triangles (video) | Khan Academy
The Converse of the Isosceles Triangle Theorem states that if two base angles, or two angles that are consecutive, are congruent, then the triangle must be congruent.
Finding angles in isosceles triangles (example 2) - Khan Academy
Sal combines what we know about isosceles triangles and parallel lines with the power of algebra to solve the angles of an isosceles triangle. Created by Sal Khan.
Isosceles & equilateral triangles problems - Khan Academy
Isosceles triangles have two congruent sides and two congruent base angles. Equilateral triangles have all side lengths equal and all angle measures equal. We use these properties to find missing angles …
Standards Mapping - Common Core Math | Khan Academy
Use the definition of congruence in terms of rigid motions to show that two triangles are congruent if and only if corresponding pairs of sides and corresponding pairs of angles are congruent.
Corresponding parts of congruent triangles are congruent
Definition: Triangles are congruent when all corresponding sides and interior angles are congruent. The triangles will have the same shape and size, but one may be a mirror image of the other. One way to …
Geometric constructions: perpendicular bisector - Khan Academy
It cuts the line in half and can create any number of isosceles triangles along the perpendicular bisector. We use the concept in equilateral triangles also to work with special right triangles.